Euler Problem 31 ...

It's just a integer partition.
public class Test {
  static int count = 0;

  public static void main(String[] args) {
    partition(200, 200);
    System.out.println(count);
  }

  public static void partition(int n, int max) {
    if (n == 0) {
      count++;
      return;
    }

    for (int i = Math.min(max, n); i >= 1; i--) {
      if (i == 200 || i == 100 || i == 50 || i == 20 
          || i == 10 || i == 5 || i == 2 || i == 1)
        partition(n - i, i);
    }
  }

}

73682
Job Finished in 0.02 seconds
정수론에서 나오는 자연수 분할 문제 ..

Euler 40 for Java: Finding the nth digit of the fractional part of the irrational number

Simply, the Integer array can be used to write digits.
public class Test {
  static int[] x = new int[1000000];
  static int index = 0;
  public static void main(String[] args) {
    for (int i = 1; i < x.length; i++) {
      if(index >= x.length)
        break;
      
      append(i);
    }
    
    System.out.println(d(1) * d(10) * d(100) * d(1000) * d(10000) * d(100000) * d(1000000));
  }
  
  private static int d(int i) {
    return x[i - 1];
  }
  
  private static void append(int n) {
    String a = String.valueOf(n);
    for(int i = 0; i < a.length(); i++) {
      if(index >= x.length)
        break;
      
      x[index] = Integer.valueOf(String.valueOf(a.charAt(i)));
      index++;
    }
  }
}